5/4y^2+y=y^2

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Solution for 5/4y^2+y=y^2 equation: 



5/4y^2+y=y^2

We move all terms to the left:

5/4y^2+y-(y^2)=0



Domain of the equation: 4y^2!=0

y^2!=0/4

y^2!=√0

y!=0

y∈R



determiningTheFunctionDomain
-y^2+5/4y^2+y=0

We add all the numbers together, and all the variables

-1y^2+y+5/4y^2=0

We multiply all the terms by the denominator


-1y^2*4y^2+y*4y^2+5=0

Wy multiply elements

-4y^4+4y^3+5=0

We do not support eypression: y^4

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